Question

Rationalise the denominator of 1/ 3- root 2 +root 5​

Answer 1

Ans:- 1/(3-√2+√5)

= 1/(3-√2+√5)×(3+√2-√5)/(3+√2-√5)

= (3+√2-√5)/9-2+5

= 3/10 + √2/10 - √5/10

here is your answer

hope it will help you

Answer 2

S O L U T I O N ✯

$\begin{gathered} \Large \tt \: \frac{1}{ \sqrt{3} + \sqrt{5} } \\ \end{gathered}$

$\boxed{\rm \: Rationalizing \: \: Factor \: \: is \: \: \sqrt{3} - \sqrt{5} }$

$\begin{gathered} \sf \: \frac{1}{ \sqrt{3} + \sqrt{5} } = \bf \: \frac{1}{ \sqrt{3} + \sqrt{5} } \: \times \: \frac{ \sqrt{3} \: - \: \sqrt{5} }{ \sqrt{3} \: - \: \sqrt{5} } \\ \\ \\ \bf \: \: = \: \frac{ \sqrt{3} \: - \: \sqrt{5} }{ { ( \sqrt{3} \: )^{2} \: - \: ( \sqrt{5} \: )^{2} } } = \frac{ \sqrt{3} \: - \: \sqrt{5} }{3 \: - \: 5 \: } \\ \\ \\ \bf \: = \: \frac{ \sqrt{3} \: - \: \sqrt{5} }{ \: - \: 2} \: = \: \frac{ \sqrt{5} \: - \: \sqrt{3} }{2} \\ \end{gathered}$