Question

rationalise the denominator of 1/3-root2
plz explain ​

Answer 1

AnSwEr :-

$\dfrac{1}{3 - \sqrt{2} }$

→ $\sf \dfrac{1}{3 - \sqrt{2}} \times \dfrac{3 + \sqrt{2}}{3 + \sqrt{2} }$

→ $\sf \dfrac{3 + \sqrt{2}}{ {(3)}^{2} - \sqrt{ {(2)}^{2} } }$

→ $\sf\dfrac{3 + \sqrt{2}}{9 - 2}$

→$\sf \dfrac{3 + \sqrt{2}}{7}$

Procedure :-

→ This question is from the chapter number system. First we will see the equation after seeing it we will multiply the denominator with both numerator as will as again with denominator again.

→ The sign will change from negetive (-) to positive (+), after that will we equate the numerator. After that we will do the square of the constants given in denominator √2 will be 2 because √2× √2 =√4 = 2.

→ We will put negetive (-) sign because an algebraic identity is being used here which is (a+b) (a-b) = a²- b². After that we will subract 9 from 2 and the remaining answer will be 3+√2/7 that is your final answer.

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