rationalise the denominator of 1/5+2√3
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Given :-
- 1/5 + 2√3
To find :-
- Rationalize the denominator
Solution :-
→ 1/5 + 2√3
- Rationalize its denominator
→ 1/5 + 2√3 × 5 - 2√3/5 - 2√3
- Apply identity
- a² - b² = (a + b)(a - b)
→ 5 - 2√3/(5)² - (2√3)²
→ 5 - 2√3/25 - 12
→ 5 - 2√3/13
Hence,
- 5-2√3/13 is the value after rationalising 1/5 + 2√3
Some more identities
- (a + b)³ = a³ + b³ + 3ab(a + b)
- (a - b)³ = a³ - b³ - 3ab(a - b)
- a³ - b³ = (a - b)(a² + ab + b²)
- a³ + b³ = (a + b)(a² - ab + b²)
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