Question

rationalise the denominator of
1/(√6-√3) ​

Answer 1

Answer:

(√2+1)/√3

Step-by-step explanation:

1/(√6-√3) * (√6 + √3)/(√6 - √3)

(√6 + √3)/3

(√2√3 + √3)/3

(√2 + 1)/√3

Answer 2

Answer:

√6+√3/3

Step-by-step explanation:

1/(√6 - √3)

1/√6 - √3 × √6 + √3/√6 + √3

by using a²-b² = (a+b)(a-b)

√6 + √3/(√6)² - (√3)²

√6 + √3/6 - 3

√6 + √3/3