Math, asked by nn3644868, 2 months ago

rationalise the denominator of 1/(√6-√3)​

Answers

Answered by sunnatemuslima
1

Answer:

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Answered by bagkakali
0

Answer:

1/(√6-√3)

=1(√6+√3)/(√6+√3)(√6-√3)

=(√6+√3)/(√6^2-√3^2)

=(√6+√3)/(6-3)

=(√6+√3)/3

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