Question

Rationalise the denominator of 1/6+root5

Answer 1

Answer:

6-√5/31

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Step-by-step explanation:

Answer 2

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Rationalise the denominator of 1/6+root5

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$\bold{= > \frac{1}{6 + \sqrt{5} }}$

$\bold{= > \frac{1}{6 + \sqrt{5} } \times \frac{6 - \sqrt{5} }{6 - \sqrt{5} }}$

Here ,this identity is used :-

$\bold{\boxed{\pink{(x + y)(x - y) = {x}^{2} - {y}^{2}}}}$

$\bold{= > \frac{6 - \sqrt{5} }{ {(6)}^{2} - {( \sqrt{5}) }^{2} } }$

$\bold{= > \frac{6 - \sqrt{5} }{36 - 5}}$

$\bold{= > \frac{6 - \sqrt{5} }{31}}$

$\huge\mathcal{Learn\:more:}$

• The result we get e.g.=6-√5/31 is a rational number as it is in the form of a rational number where ,q(denominator) is not equal to 0
• If any value is negative inside root say √-5 then we can replace - sign by 'i' (iota)

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