Rationalise the denominator of 1÷√7-1
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1 / (√7-1)
= 1 (√7+1) / (√7-1) (√7+1) [By the identity: (a+b) (a-b) = a^2 - b^2 ]
= √7+1 / (7-1)
= √7+1 / 6
= 1 (√7+1) / (√7-1) (√7+1) [By the identity: (a+b) (a-b) = a^2 - b^2 ]
= √7+1 / (7-1)
= √7+1 / 6
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