Math, asked by vayushrawal7576, 6 hours ago

rationalise the denominator of 1/√7-2​

Answers

Answered by xXmonaXx99
4

Answer:

{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Question}}}}}}}}}}}}}

rationalise the denominator of 1/√7-2

{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}

firstly, change the sign of the denominator , i.e √7 - √2 will become √7 + 2 , so multiply this term both with numerator and denominator. Multiply the terms , and we know that (a+b)(a-b) = a² - b² , use this identity for denominator! solve it more , square root and square will cancel out!

{\huge{\star{\underbrace{\mathbb{\red{Ans By Mona}}}}}}{\huge{\star}}

\huge\sf\fbox\pink{Follow Plz}

Answered by Anonymous
2

\Huge{\textbf{\textsf{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}

firstly, change the sign of the denominator , i.e √7 - √2 will become √7 + 2 , so multiply this term both with numerator and denominator. Multiply the terms , and we know that (a+b)(a-b) = a² - b² , use this identity for denominator! solve it more , square root and square will cancel out!

Attachments:
Similar questions