Question

Rationalise the denominator of 1/7+√3

Answer 1

Answer:

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Answer 2

Answer:

$= \frac{1}{7 + \sqrt{3} } \\ = \frac{(7 - \sqrt{3}) }{(7 + \sqrt{3} )(7 - \sqrt{3}) } \\ = \frac{7 - \sqrt{3} }{ {7}^{2} - { \sqrt{3} }^{2} } \\ = \frac{7 - \sqrt{3} }{49 - 3} \\ = \frac{7 - \sqrt{3} }{46}$