Question

:Rationalise the denominator of 1/7+3√2​

Answer 1

Step-by-step explanation:

we have,

$\rm \qquad \quad \dfrac{1}{7+3\sqrt{2}}$

$\rm \quad \quad \dfrac{1}{7+3\sqrt{2}}×\dfrac{7-3\sqrt{2}}{7-3\sqrt{2}}$

$\rm \qquad \quad \dfrac{7-3\sqrt{2}}{(7)^2-(3\sqrt{2})^2}$

$\rm \qquad \quad \dfrac{7-3\sqrt{2}}{49-18}$

$\rm \qquad \qquad \dfrac{7-3\sqrt{2}}{31}$