Question

rationalise the denominator of 1/7+3√3​

Answer 1

Step-by-step explanation:

$= \frac{1}{ 7+ 3 \sqrt{3} } \\ = \frac{1}{7 + 3 \sqrt{3} } \times \frac{7 - 3 \sqrt{3} }{7 - 3\sqrt{3} } \\ = \frac{7 - 3 \sqrt{3} }{ {7}^{2} - {(3 \sqrt{3} )}^{2} } \\ = \frac{7 - 3 \sqrt{3} }{49 - 27} \\ = \frac{7 - 3 \sqrt{3} }{22}$