Question

Rationalise the denominator of 1/[7+√3]

Answer 1

2413252424wtrte3

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Answer 2

Question :-

Rationalise the denominator of $\sf{{\dfrac{1}{7+{\sqrt{3}}}}}$

Answer :-

Multiply $\sf{7-{\sqrt{3}}}$ in both numerator and denominator .

$\sf{={\dfrac{1×(7-{\sqrt{3}})}{(7+{\sqrt{3}})(7-{\sqrt{3}})}}}$

$\sf{={\dfrac{1×(7-{\sqrt{3})}}{7^2-({\sqrt{3})^2}}}}$

$\sf{={\dfrac{7-{\sqrt{3}}}{46}}}$