Question

Rationalise the denominator of .

1
/7 + √3
please answer it is urgent​

Answer 1

Given :

$➠ \: \frac{1}{ {7} + \sqrt{3} }$

Solution :

$➠ \: \frac{1}{7 + \sqrt{3} }$

$➠ \: \frac{1}{7 + \sqrt{3} } \times \frac{7 - \sqrt{3} }{7 - \sqrt{3} }$

• We use the identity [ (a+b) (a-√b) = a² - b ]

$➠ \: \frac{7 - \sqrt{3} }{49 - 3} = \frac{7 - \sqrt{3} }{46}$

$➠ \: { \sf{Answer \: is = { \boxed{ \blue{ \sf{\frac{7 - \sqrt{3} }{46}}}}}}} \star$

_________________________

• So, when the denominator of an expression contains a term with a square root (or a number under radical sign), the process of converting it to an equivalent expression whose denominator is a rational number is called rationalising the denominator.

Answer 2

Answer:

Of course u can get the names...

Step-by-step explanation:

1. varadad25

2. CuteCandy

I hope ur issue will be soon resolved