Question

Rationalise the denominator of 1 / 8-3 √5

Answer 1

Answer:

$\dfrac{8+3\sqrt{5}}{19}$

Step-by-step explanation:

We have,

$\dfrac{1}{8-3\sqrt{5}}$

$\dfrac{1}{8-3\sqrt{5}} × \dfrac{8+3\sqrt{5}}{8+3\sqrt{5}}$

$= \dfrac{8+3\sqrt{5}}{(8)^2-(3\sqrt{5})^2}$

$= \dfrac{8+3\sqrt{5}}{64-9×5}$

$= \dfrac{8+3\sqrt{5}}{64-45}$

$= \dfrac{8+3\sqrt{5}}{19}$

Answer 2

Answer:

$\frac{1}{8 - 3 \sqrt{5} } \\ \frac{1}{8 - 3 \sqrt{5} } \times \frac{8 + 3 \sqrt{5} }{8 + 3 \sqrt{5} } \\ \frac{8 + 3 \sqrt{5} }{8 {}^{2} - (3 \sqrt{5) {}^{2} } } \\ \frac{ 8+ 3 \sqrt{5} }{64 - 45} \\ \frac{8 + 3 \sqrt{5} }{19}$

this is the correct answer of your question

Step-by-step explanation:

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