Question

rationalise the denominator of 1 by 3+✓2​

Answer 1

$\frac{1}{3 + \sqrt{2} }$

$\frac{1}{3 + \sqrt{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} }$

$\frac{3 - \sqrt{2} }{(3) {}^{2} - ( \sqrt{2) {}^{2} } }$

$\frac{3 - \sqrt{2} }{9 - 2}$

$\frac{3 - \sqrt{2} }{7}$

$\large{vergilmustdie}$

Answer 2

Step-by-step explanation:

$\frac{1}{3 + \sqrt{2} } \\ = \frac{1}{3 + \sqrt{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} } \\ = \frac{3 - \sqrt{2} }{ {3}^{2} - { \sqrt{2} }^{2} } \\ = \frac{3 - \sqrt{2} }{9 - 2} \\ = \frac{3 - \sqrt{2} }{7} \\ \\ hope \: its \: helps \: u...... \\ \\ \\ plz \: mark \: as \: brainliest........$