Rationalise the denominator of 1/(root 3 + root 2 - root 6)
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1/(√3+√2-√6)
1×(√3+√2+√6)/(√3+√2-√6)×(√3+√2+√6)
√3+√2+√6/{(√3+√2)²-(√6)²}
√3+√2+√6/{(√3)²+(√2)²+2√6-6}
√3+√2+√6/2√6-1
(√3+√2+√6)×(2√6+1)/{(2√6)²-1²
(2√18+2√12+2√36+√3+√2+√6)/(24-1)
(6√2+4√3+12+√3+√2+√6)/23
(7√2+5√3+12)/23
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1×(√3+√2+√6)/(√3+√2-√6)×(√3+√2+√6)
√3+√2+√6/{(√3+√2)²-(√6)²}
√3+√2+√6/{(√3)²+(√2)²+2√6-6}
√3+√2+√6/2√6-1
(√3+√2+√6)×(2√6+1)/{(2√6)²-1²
(2√18+2√12+2√36+√3+√2+√6)/(24-1)
(6√2+4√3+12+√3+√2+√6)/23
(7√2+5√3+12)/23
PLEASE SELECT MY ANSWERS AS BRAINLIEST
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