Math, asked by mari22, 1 month ago

rationalise the denominator of 1/ root 5 minus root3

Answers

Answered by kolkatafoodcenter

0

Answer:

1/√5+√3= 1/√5+√3×√5-√3/√5-√3 = √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2} =√5-√3/5-3 =√5-√3/2 ans

Answered by anushkapal2007

0

Answer:

your answer is 5+root3 upon 22

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