rationalise the denominator of 1+ root 6/7+3 root 2
Answers
Answered by
2
Step-by-step explanation:
Given that:
6
−
3
6
+
3
Here R.F of
6
−
3
is
6
+
3
=
6
−
3
6
+
3
×
6
+
3
6
+
3
=
(
6
)
2
−(
3
)
2
(
6
+
3
)
2
∵(a−b)(a+b)=a
2
−b
2
=
6−3
(
6
)
2
+(
3
)
2
+2
6
×
3
∵(a+b)
2
=a
2
+2ab+b
2
=
3
6+3+2
18
=
3
9+6
2
=
3
3(3+2
2
)
=3+2
2
∴
6
+
3
6
+
3
=3+2
2
Answered by
5
Answer:
Here is the answer =>
Step-by-step explanation:
1/√6/7+3√2=>
1+6/7+3√2*7-3√2/7-3√2
7-3√2+7√6-3√12/7^2-3√^2
14-3√2-6√3+7√6/49-18
14-3√2-6√3+7√6/31
So (14-3√2-6√3+7√6)/31 is the required answer.
HOPE IT HELPS.
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