Question

rationalise the denominator of 1/ root 6 minus root 3​

Answer 1

Answer:

Hi ,

1/( √7 - √6 )

= ( √7 + √6 )/[ (√7 - √6 )(√7 + √6 ) ]

= ( √7 + √6 )/ [ ( √7 )² - ( √6 )² ]

= ( √7 + √6 )/ ( 7 - 6 )

= √7 + √6

I hope this helps you.

: )

Answer 2

√6-√3 = √6 + √3

1. √6^2 + √3^2

√6+ √3

( 6 )^2 + ( 3)^2

√6 + √3

36 + 9

√6 + √3

45