Math, asked by ggjvgjjj247, 1 year ago

Rationalise the denominator of. 1/root7- 2

Answers

Answered by PASUPULETIDURGA
1

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Answered by Salmonpanna2022
1

Step-by-step explanation:

tex] \bf \underline{Solution-} \\ [/tex]

 \frac{1}{ \sqrt{7} -2}  \\

 =  \frac{1}{ \sqrt{7}  - 2}  \times  \frac{ \sqrt{7}  + 2}{ \sqrt{7} + 2 }  \\

 =  \frac{1( \sqrt{7} + 2) }{( \sqrt{7}  - 2)( \sqrt{7}  + 2) }  \\

 =  \frac{ \sqrt{7}  + 2}{( \sqrt{7}  {)}^{2} - ( 2 {)}^{2}   }  \\

 =  \frac{ \sqrt{7} + 2 }{7 - 4}  \\

 =  \frac{ \sqrt{7}  + 2}{3}  \\

 \bf{Hence \:  the \:  denominator \:  is  \: rationalised.} \\

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