Math, asked by argamerlegend, 7 months ago

Rationalise the denominator of
1/underoot7-2​

Answers

Answered by kasareanita5
0

Answer:

45414962149615162651418421654189471841

Step-by-step explanation:

Answered by sivasridhar
2

Answer:

 \frac{1}{ \sqrt{7 - 2} }

firstly, change the sign of the denominator , i.e √7 - √2 will become √7 + 2 , so multiply this term both with numerator and denominator.

 \frac{1( \sqrt{7} + 1) } {( \sqrt{} {} {7}  + 1)( \sqrt{7}  - 1)}

Multiply the terms , and we know that (a+b)(a-b) = a² - b² , use this identity for denominator!

 \frac{ \sqrt{7} - 2 }{ \sqrt{7} {}^{2}  - 2 {}^{2}  }

solve it more , square root and square will cancel out!

 \frac{ \sqrt{7}  + 2}{(7 - 4)}

 =  \frac{ \sqrt{7} - 2 }{3}

thus , after rationalising we will get :-

</u></em></strong></p><p></p><p><strong><em><u>\boxed{\frac{{\sqrt{7}} + 2}{3}}

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