Math, asked by akthakre1907, 8 months ago

rationalise the denominator of 1 upon 2 +root 7​

Answers

Answered by vimalkr626
1

Answer:

= √7+2/ 3 is the answer. firstly, change the sign of the denominator , i.e √7 - √2 will become √7 + 2 , so multiply this term both with numerator and denominator. Multiply the terms , and we know that (a+b)(a-b) = a² - b² , use this identity for denominator! solve it more , square root and square will cancel out!

Answered by monu4019
0

Answer:

1 \div 2 +  \sqrt{7}

1 2-√7

_____ * ______ =>

2+√7 2-√7

2-√7 2-√7

________ => _______

4-7 -3

=> -( 2-√7)

_________

3

=> √7-2

_______

3

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