Math, asked by naziatehaseen, 6 months ago

Rationalise the
denominator of
1by2plusroot3​

Answers

Answered by gpvvsainadh
2

Answer:

[tex] \frac{1}{2 + \sqrt{3} } \\ \frac{2 - \sqrt{3} }{(2 + \sqrt{3} )(2 - \sqrt{3}) } \\ \frac{2 - \sqrt{3} }{ {2}^{2} - { (\sqrt{3}) }^{2} } \\ \frac{2 - \sqrt{3} }{4 - 3} \\ \frac{2 - \sqrt{3} }{1} \\ 2-sqrt{3}

Answered by ashounak
1

Answer:

2 -  \sqrt{3}

Step-by-step explanation:

 \frac{1}{2 +  \sqrt{3 } }  \\  \frac{1}{2 +  \sqrt{3} }   \times  \frac{2 -  \sqrt{3} }{2 -   \sqrt{3} }  \\ \frac{2 -  \sqrt{3} }{ {2}^{2} - 3 }   \\  \frac{2 -  \sqrt{3} }{4 - 3}  \\ 2 -  \sqrt{3}

Hope it helps.

Plz mark branliest.

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