Question

Rationalise the denominator of 2/ 2-√3

Answer 1

2/2-√3

Rationalising factor is 2+√3.

So, multipling and dividing by 2+√3.

= 2/2-√3 × 2+√3/2+√3

= 2(2+√3) / (2-√3)(2+√3)

= 4+2√3 / 2²-(√3)² [ (a+b) (a-b) = a²-b²) ]

= 4+2√3 / 4-3

= 4+2√3 /1

= 4+2√3

Answer is 4+2√3.

:)

Answer 2

Heyy !
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$\frac{2}{2- \sqrt{3} }$

Rationalizing  the denominator 

$\frac{2}{2- \sqrt{3} } X \frac{2+ \sqrt{3} }{2+ \sqrt{3} } [tex] \frac{4+2 \sqrt{3} }{2^2- \sqrt{3} ^2} [tex] \frac{4+2 \sqrt{3} }{4-3} [tex] \frac{4+ 2\sqrt{3} }{1} <span>[tex] </span>4+2 \sqrt{3}$