Question

Rationalise the denominator of:
(√2)/(√2+ √3-√5)

Answer 1

Step-by-step explanation:

answer is short is 16

explanation is in photo

Answer 2

$\mathbf{QUESTION\:-}\\Rationalise \:the \:denominator\: of\::\frac{\sqrt{2}}{\sqrt{2}+\sqrt{3}-\sqrt{5}}\\\\\mathbf{SOLUTION\:-}\\\\\Rightarrow \frac{\sqrt{2}}{\sqrt{2}+\sqrt{3}-\sqrt{5}}\\\Rightarrow \frac{\sqrt{2}}{\sqrt{2}+\sqrt{3}-\sqrt{5}}\:\times \frac{\sqrt{2}-\sqrt{3}+\sqrt{5}}{\sqrt{2}-\sqrt{3}+\sqrt{5}}$

$\\\Rightarrow \frac{\sqrt{2}\times(\sqrt{2}-\sqrt{3}+\sqrt{5})}{(\sqrt{2}-\sqrt{3})^{2}-(\sqrt{5})^{2}}\\\Rightarrow \frac{2-\sqrt{6}+\sqrt{10}}{2-2\sqrt{6}+3-5}\\\Rightarrow \frac{2-\sqrt{6}+\sqrt{10}}{-2\sqrt{6}}\\\Rightarrow \frac{2-\sqrt{6}+\sqrt{10}}{-2\sqrt{6}}\times\frac{\sqrt{6}}{\sqrt{6}}$

$\\\Rightarrow \frac{2\sqrt{6}-6+\sqrt{60}}{-12}\\\Rightarrow \frac{6-2\sqrt{6}-2\sqrt{15}}{12}\\\Rightarrow \frac{3-\sqrt{6}-\sqrt{15}}{6}\\\\\mathbf{HOPE\:IT\:MAY\:HELP\:YOU...}$