Math, asked by Gursimransyan6, 11 months ago

Rationalise the denominator of 2√2-√5/2√2+3√3

Answers

Answered by jaiswalladdu9
0

Answer:

do not know that question

Answered by pp7733001502
1

Step-by-step explanation:

=2√2-√5/2√2+3√3*2√2-3√3/2√2-3√3

=2√2(2√2-3√3)-√5(2√2-3√3)/(2√2+3√3)(2√2-3√3)

=(2√2*2√2)-(2√2*3√3)-(√5*2√2)-(√5*3√3)/(2√2)^2-(3√3)^2

4√4-6√6-2√10-3√15/8-18

=4√4-6√6-2√19-3√15/-10. Answer

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