Math, asked by avtarsingh091207, 3 months ago

Rationalise the denominator of 2+√3 / 2-√3​

Answers

Answered by mk8471139
1

Step-by-step explanation:

 \frac{2 +  \sqrt{3} }{2 -  \sqrt{3} }  \times  \frac{ 2 + \sqrt{3} }{2 +  \sqrt{3} }  \\  \\  =  \frac{(2 +  \sqrt{3} {)}^{2}  }{ {2}^{2} -  { \sqrt{3} }^{2}  }  \\  \\  =   \frac{ {2}^{2}  +  { \sqrt{3} }^{2}  + 2 \times 2 \times  \sqrt{3} }{4 - 3}  \\   \\  =  \frac{4 + 3 + 4 \sqrt{3} }{1}  \\  \\  = 7 + 4 \sqrt{3}

Answered by gss83638
2

Answer:

(7 + 4√3)

Step-by-step explanation:

(2+√3 / 2-√3) × (2+√3 / 2+√3)

= (2+√3)^2 / (4-3)

= (4+3+4√3)/1

= (7 + 4√3)

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