Question

rationalise the denominator of 2√3+5√7÷√5+√6

Answer 1

$\frac{(2 \sqrt{3} + 5 \sqrt{7}) }{ \sqrt{5} - \sqrt{6} } \times \frac{ \sqrt{5} + \sqrt{6} }{ \sqrt{5} + \sqrt{6} } \\ \\ \frac{2 \sqrt{15} + 2 \sqrt{18} + 5 \sqrt{35} + 5 \sqrt{42} }{5 - 6} \\ \\ - 2( \sqrt{15} + \sqrt{18} ) - 5( \sqrt{35} + \sqrt{42} )$

Answer 2

Hi here is the answer

(2√3+5√7)/(√5+√6)

Rationalising denominator is making the denominator as a rational number so we have to multiply and divide the fraction by the conjugate of the denominator.
The denominator is √5+√6
So conjugate will be √5-√6
(2√3+5√7 * √5-√6)/([√5+√6][√5-√6]
2√15+5√35-2√18+5√42 / 5-6
So the final answer when u rationalise is

-[ 2√15+5√35-2√18+5√42]

Can you please mark it as brainliest
I hope you understood...........