Question

rationalise the denominator of 2/(√3+√7)

Answer 1

Step-by-step explanation:

2/(√3+√7) =

$\frac{2( \sqrt{3} - \sqrt{7} )}{( \sqrt{3} + \sqrt{7} ) \times ( \sqrt{3} - \sqrt{7} )} = \frac{2( \sqrt{3} - \sqrt{7}) }{3 + 7} =$

$0.2 \times ( \sqrt{3} - \sqrt{7})$

Answer 2

Answer:

$\frac{2}{ \sqrt{3} + \sqrt{7} } \times \frac{ \sqrt{3} - \sqrt{7} }{ \sqrt{3} - \sqrt{7}} \\ \frac{2( \sqrt{3} - \sqrt{7)} }{ { (\sqrt{3} }^{2} - { \sqrt{7} }^{2}) } \\ \frac{2 \sqrt{3} - 2 \sqrt{7} }{(3 - 7)} \\ \frac{2( \sqrt{3} - \sqrt{7)} }{ - 4} \\ \frac{ \sqrt{3} - \sqrt{7} }{ - 2}$

Step-by-step explanation:

Mark in brainlest plzz