Math, asked by Mayank200627, 8 months ago

Rationalise the denominator of √2+√5/√2-√5​

Answers

Answered by spacehimanshu
2

see the image and let me know if you understand

Attachments:
Answered by brainlyaryan12
10

✪  \huge{\underline{\overline{\mathbf{Question}}}}  ✪

→Rationalise the denominator of √2+√5/√2-√5

✪  \huge{\underline{\overline{\mathbf{Answer}}}}  ✪

\Large{\frac{\sqrt{2}+\sqrt{5}}{\sqrt{2}-\sqrt{5}}}

\frac{\sqrt{2}+\sqrt{5}}{\sqrt{2}-\sqrt{5}}\times \frac{\sqrt{2}+\sqrt{5}}{\sqrt{2}+\sqrt{5}}

\frac{(\sqrt{2}+\sqrt{5})^2}{(\sqrt{2}-\sqrt{5})(\sqrt{2}+\sqrt{5})}

\frac{(\sqrt{2}+\sqrt{5})^2}{(\sqrt{2})^2-(\sqrt{5})^2}

\frac{(\sqrt{2})^2+(\sqrt{5})^2+2\sqrt{10}}{2-5}

\frac{2+5+2\sqrt{10}}{-3}

\huge{\pink{\frac{-(7+2\sqrt{10})}{3}}}

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Formulas Used :-

  • \large{(a+b)(a-b)=a^2-b^2}
  • (a+b)^2=a^2+b^2+2ab

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