Math, asked by KRISH1111111111, 1 year ago

rationalise the denominator of 2√5+3√2/2√5-3√2

Answers

Answered by lakshman12
0

2 \sqrt{5 }  + 3 \sqrt{2}  \div 2 \sqrt{5} - 3 \sqrt{2}  \times 2 \sqrt{5}   +  3 \sqrt{2}   \div 2 \sqrt{5}  + 3 \sqrt{2}
(2root5+3root2)^2÷(2)
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