Question

rationalise the denominator of 2√6/√2+√3​

Answer 1

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Answer 2

Answer:

=> 2 root 6 / root 2 + 3 = 2 root 6 / root 2 + root 3 [ root 2 - root 3 / root 2 - root 3 ].

=> 2 root 6 ( root 2 - root 3 ) / ( root 2 + root 3 ) ( root 2 - root 3 ).

=> 2 root 12 - 2 root 18 / ( root 2^2 ) - ( root 3^2 ).

=> 2 ( root 12 - root 18 ) / 2 - 3.

=> 2 ( root 2 × 2 × 3 - root 3 × 3 × 2 ) / - 1.

=> - 2 ( 2 root 3 - 3 root 2 ).

=> 2 ( 3 root 2 - 2 root 3 ).

Step-by-step explanation:

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