Rationalise the denominator of 22/2+√3+√5
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Answered by
2
Answer:
4 - 2√15 + 3√3 + √5
Step-by-step explanation:
Rationalise the denominator of 22/2+√3+√5
22/(2+√3+√5)
= 22/(2+√3+√5) * (2- (√3+√5))/(2- (√3+√5))
= 22 (2- (√3+√5)) / ( 4 - (3 + 5 + 2√15) )
= 22 (2- (√3+√5)) / ( -4 - 2√15) )
= -11 (2- (√3+√5)) / ( 2 + √15) )
= -11 (2- (√3+√5)) / ( 2 + √15) ) * (2 - √15)/(2 - √15)
= -11 (2- (√3+√5)) * (2 - √15) / ( 4 - 15)
= -11 (2- (√3+√5)) * (2 - √15) /(-11)
= (2- (√3+√5)) * (2 - √15)
= 4 - 2√15 - 2√3 - 2√5 + 3√5 + 5√3
= 4 - 2√15 + 3√3 + √5
Answered by
0
Answer:
11+root8/3
Step-by-step explanation:
22/2+root3+root6
=> 22/2+root8
=> 22*2+root8/2+root8*2+root8
=> 44+root8/12
=> 11+root8/3
hope it helps you
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