Question

rationalise the denominator of (3√2+2√3) /(3√2-2√3)​

Answer 1

Answer:

hope you help this solution ☺️☺️☺️☺️

Answer 2

Answer:

       5 + 2√6

Step-by-step explanation:

Multiply numerator and denominator by a conjugate of the denominator to eliminate radicals in the denominator (i.e. rationalise):

$\displaystyle\frac{3\sqrt2+2\sqrt3}{3\sqrt2-2\sqrt3}\\\\=\frac{(3\sqrt2+2\sqrt3)\times(3\sqrt2+2\sqrt3)}{(3\sqrt2-2\sqrt3)\times(3\sqrt2+2\sqrt3)}\\\\=\frac{(3\sqrt2)^2+(2\sqrt3)^2+2(3\sqrt2)(2\sqrt3)}{(3\sqrt2)^2-(2\sqrt3)^2}\\\\=\frac{18+12+12\sqrt6}{18-12}\\\\=\frac{30+12\sqrt6}{6}\\\\=5+2\sqrt6$