Question

rationalise the denominator of 3/√5-√2​

Answer 1

Answer:

HEY MATE...

GOOD NOON ♦

3/√5 - √2

MULTIPLYING NUMERATOR AND DENOMINATOR BY √5 + √2

3√5 + 3√2 / 5 - 2

3(√5 - √2) /3

3 gets cancelled

√5 - √2

HOPE IT HELPS !!!

Answer 2

Answer:

$\frac{3}{ \sqrt{5} - \sqrt{2} } \\ = \frac{3}{ \sqrt{5} - \sqrt{2} } \times \frac{ \sqrt{5} + \sqrt{2} }{ \sqrt{5} + \sqrt{2} } \\ = \frac{3 \sqrt{5} + 3 \sqrt{2} }{( \sqrt{5} ) {}^{2} - ( \sqrt{2}) {}^{2} } \\ = \frac{3( \sqrt{5} - \sqrt{2} )}{5 - 2} \\ = \frac{3( \sqrt{5} - \sqrt{2}) }{3} \\ = \sqrt{5} - \sqrt{2}$

Hence rationalized