Question

Rationalise the denominator of 3-√5/3+√5

Answer 1

Rationalise the denominator of 3-√5/3+√5

Step-by-step explanation:

$\frac{3 - \sqrt{5} }{3 + \sqrt{5} }$

$\frac{3 - \sqrt{5} }{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5} }$

$\frac{ {3}^{2} - 2 \times 3 \times \sqrt{5} + {( \sqrt{5)} }^{2} }{ {3}^{2} - {( \sqrt{5)} }^{2} }$

$\frac{9 - 6 \sqrt{5} + 5}{9 - 5}$

$\frac{14 - 6 \sqrt{5} }{4}$

$\frac{2(7 - 3 \sqrt{5} )}{4}$

7-3√5/2 is the answer...

Answer 2

rationalise = 3 - √5/3 + √5 × 3 - √5/3 - √5

= (3 - √5)²/(3)² - (√5)²

= (3)² + (√5)² - 2(3)(√5)/9 - 5

= 9 + 5 - 6√5/4

= 14 - 6√5/4

= 2(7 - 3√5)/4

= 7 - 3√5/2

I hope this help you

thanks