Question

Rationalise the denominator of: 3+√5/4+√5

Answer 1

Answer:

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Answer 2

Answer:

$\frac{3 + \sqrt{5} }{4 + \sqrt{5} } \\ = > \frac{3 + \sqrt{5} }{4 + \sqrt{5} } \times \frac{4 - \sqrt{5} }{4 - \sqrt{5} } \\ \frac{3 + \sqrt{5} (4 - \sqrt{5}) }{ {4}^{2} - \sqrt{5} ^{2} } \\ \frac{12 - 3 \sqrt{5} + 4 \sqrt{5} - \sqrt{25} }{16- 5} \\ \frac{12 - 5 - 3 \sqrt{5} + 4 \sqrt{5} }{11} \\ \frac{7 + \sqrt{5} }{11}$