Question

rationalise the denominator of 3 plus root 3 by 2 plus root 3

Answer 1

Answer:

$\huge\boxed{\fcolorbox{blue}{orange}{HELLO\:MATE}}$

=$\dfrac{3+\sqrt{3}}{2+\sqrt{3}}$

=$\dfrac{(3+\sqrt{3})(2-\sqrt{3})}{(2+\sqrt{3}) (2-\sqrt{3})}$

=$\dfrac{(3+\sqrt{3})(2-\sqrt{3})}{(2) ^{2}-(\sqrt{3}) ^{2}}$

$\large\green{\boxed{(a+b) (a-b) =a^{2}-b^{2}}}$

=$\dfrac{(3+\sqrt{3})(2-\sqrt{3}) }{4-3}$

=$\dfrac{(3+\sqrt{3})(2-\sqrt{3}}{1 }$

=$3(2-\sqrt{3}) +\sqrt{3}(2-\sqrt{3})$

=$6-3\sqrt{2}+2\sqrt{3}-3$

=$3-\sqrt{3}$

$\huge\orange{\boxed{Answer:3-\sqrt{3}}}$