Question

rationalise the denominator of 3-root 2and
3+root 2
​

Answer 1

Answer:

11-6✓2/7

Step-by-step explanation:

i hope it's helpful

tq

Answer 2

Answer:

$\frac{7}{11 + 6\sqrt{2} }$

Step-by-step explanation:

$\frac{3 - \sqrt{2} }{3 + \sqrt{2} }$

$= \frac{3 - \sqrt{2} }{3 + \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} }$

$= \frac{(3 - \sqrt{2)}(3 + \sqrt{2)} }{( {3 + \sqrt{2)} }^{2} }$

$= \frac{ {(3)}^{2} - {( \sqrt{2}) }^{2} }{ {(3 + \sqrt{2}) }^{2} }$

•.• (a-b)(a+b) = (a)^2 - (b)^2

$= \frac{9 - 2}{ {(3)}^{2} + (\sqrt{ {2)}^{2} } + 2(3)( \sqrt{2)} }$

$= \frac{7}{9 + 2 + 6 \sqrt{2} }$

$= \frac{7}{11 + 6 \sqrt{2} }$