Math, asked by Maruf9275, 6 hours ago

Rationalise the denominator of 3 + root6 / 3- root6

Answers

Answered by shrirampawar249
0

Answer:

 \frac{3 +  \sqrt{6} }{3 -  \sqrt{6} }  =  \frac{3 +  \sqrt{6} }{3 -  \sqrt{6} }  \times  \frac{3 +  \sqrt{6} }{3 +  \sqrt{6} }  \\  =  \frac{ {(3 +  \sqrt{6)} }^{2} }{  { \sqrt{3} }^{2}  -  { \sqrt{6} }^{2} }  \\  =  \frac{9 + 6 + 2 \times 3 \times  \sqrt{6} }{3 - 6}  \\  =   \frac{15 + 6 \sqrt{6} }{ - 3}  \\  =  - 3( - 5 - 2 \sqrt{3)}  \div -  3 \\  =  - (5 + 2 \sqrt{3)}

Similar questions