Math, asked by yhappy878, 2 months ago

Rationalise the denominator of 4/4√5

Answers

Answered by shauryapatel2009
0

Answer:

\neq \sqrt{x} \sqrt{x} \sqrt[n]{x} \sqrt[n]{x} \sqrt[n]{x} \\ \\ \\ x^{2} \geq \geq \geq x_{123}\sqrt{x} \sqrt[n]{x} \sqrt[n]{x} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \lim_{n \to \infty} a_n  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left \{ {{y=2} \atop {x=2}} \right.

Step-by-step explanation:

this is correct

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