Question

rationalise the denominator of √40/√3

Answer 1

Answer:

hope its help you thanks........

Answer 2

Given:

√40/√3

To Find:

Rationalize the denominator.

Solution:

Rationalization of the denominator is done to remove the square and cube roots from the denominator and to make them simple to be simplified. For this, the term in the denominator is multiplied to both the numerator and denominator.

In the given rational number, the numerator is $\sqrt{40}$ and the denominator is $\sqrt{3}$.

Multiply both the numerator and the denominator of the given rational number by $\sqrt{3}$.

$\frac{\sqrt{40}}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{40} \times \sqrt{3}}{\sqrt{3} \times \sqrt{3}}\\ =\frac{\sqrt{120}}{3}$

The square root from the denominator is removed.

Thus, $\frac{\sqrt{120}}{3}$ is the rationalized form of $\frac{\sqrt{40}}{\sqrt{3}}$.