rationalise the denominator of 5+√3/7+4√3
Answers
Answered by
2
hi friend, your answer is, 53 + root 3 upon 7
Answered by
6
[(5+√3) x(7-4√3)] / (7+4√3) x (7-4√3)
=[ 35–20√3+7√3–12 ] / [49 – 48]
= [ 13 –13√3 ] / 1
= 13 ( 1 – √3 )
=[ 35–20√3+7√3–12 ] / [49 – 48]
= [ 13 –13√3 ] / 1
= 13 ( 1 – √3 )
SubhamSingha:
sorry in the first line in the denominator will be 7+4√3 , but the sum is correct
Similar questions