Question

rationalise the denominator of 5 root of 3+root of 2/root of 3+ root of 2

Answer 1

Answer:

I don't know ????????????

Answer 2

Given rational number :

$\frac{5 \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

=

$\frac{5 \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

=

$= \frac{15 + \sqrt{6} - 5 \sqrt{6} - 2 }{3 - 2}$

=

$15 - 4 \sqrt{6} - 2$

=

$13 - 4 \sqrt{6}$