Math, asked by cooperfernandes16, 1 month ago

Rationalise the denominator of 5 upon root 11 -root 6 with explanation​

Answers

Answered by hfhviyfd
1

Step-by-step explanation:

 \frac{5}{ \sqrt{11 } -  \sqrt{6}  } \\  =  \frac{5}{ \sqrt{11} -  \sqrt{6}  }   \times  \frac{ \sqrt{11  } +  \sqrt{6}  }{ \sqrt{11}  +  \sqrt{6} }  \\  =  \frac{5 \sqrt{11} + 5 \sqrt{6}  }{11 - 6}  =  \frac{5 \sqrt{11}  + 5 \sqrt{6} }{5}   \\  =  \frac{5( \sqrt{11}  +  \sqrt{6} )}{5}  =  \sqrt{11}  +  \sqrt{6}

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