Question

rationalise the denominator of √6/√3-√2​

Answer 1

Step-by-step explanation:

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Answer 2

Answer-

$\sqrt{6} \div \sqrt{3 } - \sqrt{2}$

$\sqrt{6} \div \sqrt{3} - \sqrt{2} \times \sqrt{3 } + \sqrt{2} \div \sqrt{3} - \sqrt{2}$

$\sqrt{6} \times ( \sqrt{3} + \sqrt{2} ) \div 3 - 2$

$\sqrt{18} + \sqrt{12} \div 1$

$3 \sqrt{2} + 2 \sqrt{3}$

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Answer