Question

Rationalise the denominator
of
6/3-√4​

Answer 1

Step-by-step explanation:

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Answer 2

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$\frac{6}{3 - \sqrt{4} }$

$= > \frac{6}{3 - \sqrt{4} } \times \frac{3 + \sqrt{4} }{3 + \sqrt{4} }$

$= > \frac{6(3 + \sqrt{4} )}{ ({3)}^{2} - {( \sqrt{4} )}^{2} }$

$= > \frac{18 - 6 \sqrt{4} }{9 - 4}$

$= > \frac{18 - 6 \sqrt{4} }{5}$

Hope it helps.....