Math, asked by arunimakispotta, 8 months ago

rationalise the denominator of √6-√5/√6+√5​

Answers

Answered by veeramehta09
4

√6-√5/√6+√5 * √6-√5/√6-√5

(6 - 2√30 + 5)/6-5

11-2√30

Answered by Anonymous
4

Answer:

11 - \sqrt{60}

Step-by-step explanation:

{\frac{\sqrt{6} - \sqrt{5}  }{\sqrt{6} + \sqrt{5}  } }

{\frac{\sqrt{6} - \sqrt{5}  }{\sqrt{6} + \sqrt{5}  } } X \frac{\sqrt{6} - \sqrt{5}  }{\sqrt{6} - \sqrt{5}  } = \frac{ \sqrt{6} [ \sqrt{6} - \sqrt{5 ] } - \sqrt{5} [ \sqrt{6} - \sqrt{5} ]}{ \sqrt{6}^{2} - \sqrt{5} ^{2}   }

= \frac{6 - \sqrt{30} - \sqrt{30}+ 5 }{6-5}

= \frac{11 - \sqrt{60} }{1} = 11 - \sqrt{60}

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