Question

rationalise the denominator of 6-√8/6+√8​

Answer 1

Answer:

answer is 8.35702260395515841466

Answer 2

Answer:

The answer is  $\frac{(6-\sqrt{8})^{2} }{28}$

Step-by-step explanation:

$\frac{6-\sqrt{8}}{6+\sqrt{8}}$ × $\frac{6-\sqrt{8}}{6-\sqrt{8}}$

= $\frac{(6-\sqrt{8})^{2} }{6^{2} - 8 }$

= $\frac{(6-\sqrt{8})^{2} }{28}$

The numerator can be further simplified using the identity of

$(a-b)^{2}$ = $a^{2} + b^{2} - 2ab$ , if needed.

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Regards,

Lilac584