Question

rationalise the denominator of 6 upon 3 + root 3​

Answer 1

Answer:3-√3 hope it helps!

Step-by-step explanation:

Answer 2

Hey mate ☺️

Answer:

$\frac{3 - \sqrt{3} }{1}$

Step-by-step explanation:

$\frac{6}{3 + \sqrt{3} } \\ = > \frac{6}{3 + \sqrt{3} } \times \frac{3 - \sqrt{3} }{3 - \sqrt{3} } \\ = > \frac{18 - 6 \sqrt{3} }{ {3}^{2} - { (\sqrt{3} )}^{2} } \\ = > \frac{18 - 6 \sqrt{3} }{9 - 3} \\ = > \frac{6(3 - \sqrt{3} )}{6} \\ = > \frac{3 - \sqrt{3} }{1}$

I Hope it helps you ☺️✌️✌️